Find path with SPARQL

Question

Is it possible to write generic SPARQL CONSTRUCT query that will return me the whole graph starting from root node? As result I want to have all Graph triples.

Ontology:

example:Node
  rdf:type owl:Class ;
  rdfs:subClassOf owl:Thing .

example:next
  rdf:type owl:ObjectProperty ;
  rdfs:domain example:Transformation ;
  rdfs:range example:Transformation .

example:node1 a example:Node.
example:node2 a example:Node.
example:node3 a example:Node.
example:node4 a example:Node.
example:node5 a example:Node.

Graph

example:node1 example:next example:node2.
example:node1 example:next example:node3.
example:node2 example:next example:node4.
example:node3 example:next example:node4.
example:node3 example:next example:node5.

*EDIT*

Mathematically speaking, I have a Rooted graph. And I want to get the whole graph starting from the root node.

Answer 1

1	As far as I can tell from your description, a simple `CONSTRUCT WHERE {?x example:next ?y}` will give you the result you want. link answered 13 Dec '12, 14:00 Jeen Broekstra ♦ 8.4k●3●12 accept rate: 32%

Find path with SPARQL

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