SPARQL get more than one subitem

I query an API with a simple SPARQL query:

PREFIX ...
SELECT DISTINCT *
    WHERE {
    ?item dct:date ?date .
    ?item dct:title ?title .
    ?item rdfs:info ?info .
    }

And this returns me an xml

<results>
    <result>
    <binding name='title'>
            <literal>titletitle</literal>
        </binding>
        <binding name='info'>
            <uri>link</uri>
        </binding>
        <binding name='date'>
            <literal datatype='http://www.w3.org/2001/XMLSchema#dateTime'>
                2012-12-21T02:26:00+00:00
            </literal>
        </binding>
        <binding name='item'>
            <uri>link</uri>
        </binding>
    </result>
    ...
</results>

But the problem is: I know, that there are more than one links of rdfs:info matched to this item. How can I query such that I get

...
<binding name='info'>
    <uri>link1</uri>
</binding>
<binding name='info'>
    <uri>link2</uri>
</binding>
<binding name='info'>
    <uri>link3</uri>
</binding>
...

? Is this simple, or do I need a subquery or some strange UNION? If I just try

    PREFIX ...
SELECT DISTINCT *
    WHERE {
    ?item dct:date ?date .
    ?item dct:title ?title .
    OPTIONAL (?item rdfs:info ?info1 ).
    OPTIONAL (?item rdfs:info ?info2 ).
    }

that would return all possible permutations of the values of ?info1 and ?info2. Plus, I don't know the number of info items.

If I add FILTER (?info1 != ?info2), I still get some permutations. I think from an algebraic point of view it would be possible to FILTER (?info1<?info2), to discard permutations. But how can I apply < on uris?