Generating an xsd:dateTime in shell script

Question

How would you compute an xsd:dateTime in a shell script.

I can see several candidates :

$ date --iso-8601=seconds -u
2013-01-31T16:05:35+0000

but this option seems deprecated, or :

$ date --rfc-3339=seconds -u
2013-01-31 16:06:29+00:00

Both don't return the same result... so... are there any hints I've overlooked ?

Accepted Answer

7

Both are wrong in the detail for an xsd:dateTime.

--iso-8601=seconds has timezone as 0000, not 00:00

--rfc-3339=seconds has a space

take control and use a format:

date +'%Y-%m-%dT%H:%M:%S%:z'

or more concisely:

 date '+%FT%T%:z'

link

answered 31 Jan, 13:56

AndyS ♦
9.6k●2●7
accept rate: 32%

1

Perfect. Thanks alot.

(31 Jan, 14:42) olberger

1

@olberger If this answer solved your problem don't forget to accept it, click the tick mark under the vote up/down buttons

(01 Feb, 05:03) Rob Vesse ♦