Serialising resources individually with Jena

I'm no expert on the Jena API, but I assume you can simply fire a SPARQL CONSTRUCT query and treat/process the result as a new Model. The following SPARQL query will give you back all artists, their album, and all the properties of each album:

CONSTRUCT {
   ?artist a ont:Artist ;
           iweb:hasAlbum ?album . 
   ?album ?P ?Y .
}
WHERE {
   ?artist a ont:Artist ;
           iweb:hasAlbum ?album . 
   ?album ?P ?Y .
}

If you want to do this for an invidual artist, replace ?artist with the URI of the individual (or add a filter condition).

Resource individual = yourModel.createResource(individualURI);
Model individualModel = ModelFactory.createDefaultModel();
traverseModel(yourModel, individualModel, individual);
individualModel.write(outputStream, "RDF/XML-ABBREV");

public void traverseModel (Model completeModel, Model newModel, Resource node) {
    StmtIterator subNodes = completeModel.listStatements(node, null, null);
    while (subNodes.hasNext()) {
        Statement subStmt = subNodes.next();
        newModel.add(subStmt);
        if (subStmt.getObject().isResource() && ! newModel.listStatements(subStmt.getObject(), null, null).hasNext()) traverseModel(completeModel, newModel, subStmt.getObject());
    }
}